How to calculate reinforcement steel quantity in two way slab
EXAMPLE:
Preparing a bar bending schedule of two way slab. The slab size is 3 by 4 reinforcement is 16 mm@150 mm and 10 mm@200 mm c/c shorter and longer span direction respectively. Assume the clear cover is 20 mm?
SOLUTION:
Bars that are placed in shorter span is called main bars and in longer span it is called a distribution bar.
Main bars:
First, we find out the total no of bars in the shorter span
No of bars = Total span /spacing
= 3960 mm/150 mm
= 26.4 say 27 No’s of bars
CUTTING LENGTH:
As bar is placed in shorter span which is 3 m. = Total length of span – 2 x clear cover
= 3000 – 2 x 20
= 2960 mm or 2.960 m
So we have total 27 No’s of main bars,
Total length:
= 27 x 2.960 m
= 79.92 m
Weight:
= d2/162 x length
= 16 x 16/162 x 79.92
= 126.2 kg
Distribution bar:
No of bars = total span /spacing
= 2960 mm/200 mm
=15.8 say 16 No’s
As bar is placed in longer span which is 4 m
CUTTING LENGTH:
= total length – 2 x clear cover
= 4000 – 2 x 20
= 3960 mm or 3.960 m
So we have total 16 No’s of distribution bars so the total length is
Total length:
= 3.960 x 16
= 63.36 m long bar
Weight:
= d2/162 x length
=10 x 10/162 x 63.36
= 39.1 kg
Total weight of bars:
= weight of main bar + distribution bar
= 126.2 + 39.1
= 165.3 kg
EXAMPLE:
Preparing a bar bending schedule of two way slab. The slab size is 3 by 4 reinforcement is 16 mm@150 mm and 10 mm@200 mm c/c shorter and longer span direction respectively. Assume the clear cover is 20 mm?
SOLUTION:
Bars that are placed in shorter span is called main bars and in longer span it is called a distribution bar.
Main bars:
First, we find out the total no of bars in the shorter span
No of bars = Total span /spacing
= 3960 mm/150 mm
= 26.4 say 27 No’s of bars
CUTTING LENGTH:
As bar is placed in shorter span which is 3 m. = Total length of span – 2 x clear cover
= 3000 – 2 x 20
= 2960 mm or 2.960 m
So we have total 27 No’s of main bars,
Total length:
= 27 x 2.960 m
= 79.92 m
Weight:
= d2/162 x length
= 16 x 16/162 x 79.92
= 126.2 kg
Distribution bar:
No of bars = total span /spacing
= 2960 mm/200 mm
=15.8 say 16 No’s
As bar is placed in longer span which is 4 m
CUTTING LENGTH:
= total length – 2 x clear cover
= 4000 – 2 x 20
= 3960 mm or 3.960 m
So we have total 16 No’s of distribution bars so the total length is
Total length:
= 3.960 x 16
= 63.36 m long bar
Weight:
= d2/162 x length
=10 x 10/162 x 63.36
= 39.1 kg
Total weight of bars:
= weight of main bar + distribution bar
= 126.2 + 39.1
= 165.3 kg
