If d is the diameter of a bar, ft is allowable tensile stress and fb, is allowable bond stress, the bond
length is given by
(A) ft .d/4fb
(B) ( /4). (ft .d/fb)
(C) ft .d²/fb
(D) ( /4). (ft .d3/fb)
The correct Answer Is
(A) ft .d/4fb
length is given by
(A) ft .d/4fb
(B) ( /4). (ft .d/fb)
(C) ft .d²/fb
(D) ( /4). (ft .d3/fb)
The correct Answer Is
(A) ft .d/4fb