With usual notations the depth of the neutral axis of a balanced section, is given by

Srinivasan

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Staff member
Sep 7, 2017
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1,078
mumbai
#1
With usual notations the depth of the neutral axis of a balanced section, is given by

(A) mc/t = (d - n)/n

(B) t/mc = (d - n)/n

(C) t/mc = (d + n)/n

(D) mc/t = n/(d - n)

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MOHAMMED ABDUL RAFAY

Founder Member
Staff member
Sep 7, 2017
287
127
Hyderabad
#3
With usual notations the depth of the neutral axis of a balanced section, is given by

(A) mc/t = (d - n)/n

(B) t/mc = (d - n)/n

(C) t/mc = (d + n)/n

(D) mc/t = n/(d - n)

Do reply with your answer and if possible add some description to your answer.


Once you reply, you can see the correct answer of the question, its really a fun game and learning.


You need to reply to this in order to see this content.
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