#### NORA SAID

##### Newbie
How to calculate the length of stirrups if circula column R6 @ 150 mm ??

• Vbseries007 and Murali K

#### amd007

Assume diameter of column at 400 mm

Clear cover 40mm also add half dia of bar of stirrups to get effective cover. ( say dia of bar is 10 mm then effective cover would be 40 +5=45 mm)

Stirrups bar dia assumed as 10 mm

For hook consider 10d or 75mm whichever is higher.

In circular stirrups degree of bend is considered at 135 degree. so bend = 3d

Formula:

Cutting length of stirrup = Circumference of stirrup + 2 nos of hook - 2 nos of 135-degree bend

The circumference of stirrups =2 pi R

Diameter assumed = 400 mm

Radius (r) = d/2 = 400/2=200mm

Radius of stirrups = 200 - 45 =155mm

So now lets calculate : (2 x 3.14 x 155) + (2 x 10 x 10) - ( 2 x 3 x 10) = 973.40 + 200 - 60 = 1113.40 mm

So for a column of 400mm dia the cutting length of stirrup in the above case is 1113.40 mm say 1.11 meter

Attached pls find calculator

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• Mehboob, Murali K and NORA SAID

#### NORA SAID

##### Newbie
Assume diameter of column at 400 mm

Clear cover 40mm also add half dia of bar of stirrups to get effective cover. ( say dia of bar is 10 mm then effective cover would be 40 +5=45 mm)

Stirrups bar dia assumed as 10 mm

For hook consider 10d or 75mm whichever is higher.

In circular stirrups degree of bend is considered at 135 degree. so bend = 3d

Formula:

Cutting length of stirrup = Circumference of stirrup + 2 nos of hook - 2 nos of 135-degree bend

The circumference of stirrups =2 pi R

Diameter assumed = 400 mm

Radius (r) = d/2 = 400/2=200mm

Radius of stirrups = 200 - 45 =155mm

So now lets calculate : (2 x 3.14 x 155) + (2 x 10 x 10) - ( 2 x 3 x 10) = 973.40 + 200 - 60 = 1113.40 mm

So for a column of 400mm dia the cutting length of stirrup in the above case is 1113.40 mm say 1.11 meter

Attached pls find calculator
Thank Sir for helping

• purushoothman

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