With usual notations the depth of the neutral axis of a balanced section, is given by

[Srinivasan]

With usual notations the depth of the neutral axis of a balanced section, is given by

(A) mc/t = (d - n)/n

(B) t/mc = (d - n)/n

(C) t/mc = (d + n)/n

(D) mc/t = n/(d - n)

The correct Answer Is
(D) mc/t = n/(d - n)

 

[sumbriaamit]

d

 

[MAR]

With usual notations the depth of the neutral axis of a balanced section, is given by

(A) mc/t = (d - n)/n

(B) t/mc = (d - n)/n

(C) t/mc = (d + n)/n

(D) mc/t = n/(d - n)

C