What is Design mix of M25 (1:1:2) concrete for 1 bag of cement ( 1 load in mixer )? And what is procedure to calculate it ? send the calculations ...

Dnyan Deshmukh

Staff member
In order to do conversion from volumetric to weight, we should know about the dry bulk loose density (DLBD) of materials used.

In most of the cases volumetric is measured in cft so you should determine dlbd in kg per cft.

Your proportion is 1:1:2

Cement bag is 1.25 Cft as per dlbd.

So your crush sand is 1.25 cft and 20mm is 2.5 cft according to proportion.

Now get the values of crush sand and 20mm for its dlbd.

Easiest way of calculating dlbd is take cylinder or box or cube of known volume, fill it with material and calculate its dlbd = weight / volume

If units are different then convert it to kg / cft.

Multiply the dlbd to volume of material to get weights of material in Kg.

For basalt rock dlbd of crush sand is around 45 to 50 kg / cft

For 20mm dlbd is around 45 kg/cft.

Now come to your proportion and assume above value for doing calculations.

Crush sand is 1.25 cft its dlbd say 50 Kg / cft

Its weight according to proportion would be
1.25 × 50 = 62.5 Kg

20mm
Volume is 2.5 cft and dlbd is 45 kg / cft

Weight will be 2.5 × 45 = 112.5 kg

So your proportion of aggregates by weight for 1 bag of cement will be
Cement = 50 kg
Crush Sand = 62.5 Kg
20mm = 112.5 kg.

If you follow a conventional mixes, you are making a national wastage of cement because in design mixes quantity of aggregates gets increased almost to double and cement consumption get reduced.

Above values of dlbd are given just for showing calculation. Do calculate dlbd of materials at your place and do calculations accordingly.
 
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